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RN: Compassionate Care Professional Development

Job in Woonsocket, Providence County, Rhode Island, 02895, USA
Listing for: Aperion Care
Full Time position
Listed on 2026-10-07
Job specializations:
  • Nursing
    Healthcare Nursing, RN Nurse
Salary/Wage Range or Industry Benchmark: 50000 - 72000 USD Yearly USD 50000.00 72000.00 YEAR
Job Description & How to Apply Below
Position: RN: Compassionate Care, Growth & Professional Development

Advinia Care in Rhode Island is seeking a compassionate (RN) Registered Nurse to join our team and deliver high-quality resident care in a dynamic environment. The ideal candidate holds Rhode Island RN licensure, has experience in skilled nursing or assisted living, and can work days, evenings, and weekends while collaborating with the care team to plan and evaluate resident care.

You will maintain accurate records, participate in quality improvement, and pursue ongoing professional development

As a RN:
Compassionate Care, Growth & Professional Development, you will play an important part at Aperion Care in Woonsocket, RI, United States.

We have an opening for a RN:
Compassionate Care, Growth & Professional Development in Woonsocket, RI, United States within Bio & Pharmacology & Health.

This role, RN:
Compassionate Care, Growth & Professional Development at Aperion Care, could be your next opportunity.

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